{
    "version": "https://jsonfeed.org/version/1",
    "title": "lailai's Home Blog",
    "home_page_url": "https://lailai.one/blog",
    "description": "lailai's Home Blog",
    "items": [
        {
            "id": "https://lailai.one/blog/welcome",
            "content_html": null,
            "url": "https://lailai.one/blog/welcome",
            "title": "Welcome to lailai's Blog! 👋",
            "summary": "本文为博客的开篇欢迎，说明这里将分享算法与技术笔记、读书与旅行以及偶尔的随想。",
            "date_modified": "2024-10-16T16:00:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "Notice"
            ]
        },
        {
            "id": "https://lailai.one/blog/record/xuejun-hackathon",
            "content_html": null,
            "url": "https://lailai.one/blog/record/xuejun-hackathon",
            "title": "记录：学军黑客松",
            "summary": "2026 学军黑客松记录。",
            "date_modified": "2026-10-04T16:10:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "AI",
                "Record"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P9141",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P9141",
            "title": "题解：P9141 [THUPC 2023 初赛] 乱西星上的空战",
            "summary": "本文为洛谷 P9141 的题解，枚举合法整点位移，并按事件顺序模拟空战。",
            "date_modified": "2026-08-28T08:40:32.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/math/fusible-numbers",
            "content_html": null,
            "url": "https://lailai.one/blog/math/fusible-numbers",
            "title": "数学：燃烧数",
            "summary": "本文将介绍燃烧数及其递归函数，并求出钓鱼题中的 f(3)。",
            "date_modified": "2026-08-26T13:31:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "Mathematics"
            ]
        },
        {
            "id": "https://lailai.one/blog/record/gfssm-2026-final",
            "content_html": null,
            "url": "https://lailai.one/blog/record/gfssm-2026-final",
            "title": "记录：GFSSM 2026 决赛",
            "summary": "本文记录 GFSSM 2026 决赛期间的北京行程、24 小时极限挑战、总答辩与颁奖典礼。",
            "date_modified": "2026-08-14T09:40:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "Travel",
                "Record"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P17140",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P17140",
            "title": "题解：P17140 [NOI 2026] 线段",
            "summary": "本文为洛谷 P17140 的题解，用跳过禁选前缀的动态规划统计相交图为树的线段集。",
            "date_modified": "2026-07-25T05:57:44.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/math/six-factor-inequality",
            "content_html": null,
            "url": "https://lailai.one/blog/math/six-factor-inequality",
            "title": "数学：不等式挑战（二）",
            "summary": "本文将介绍一道六因子不等式，用换元、拉格朗日乘数与判别式证明。",
            "date_modified": "2026-07-18T11:26:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "Mathematics"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/AT_arc222_f",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/AT_arc222_f",
            "title": "题解：AT_arc222_f [ARC222F] Triple Transformation",
            "summary": "本文为洛谷 AT_arc222_f 的题解，把操作在模 S 下化为乘 ±2，用 BSGS 求最小操作次数。",
            "date_modified": "2026-07-12T15:51:10.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "AtCoder"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P3846",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P3846",
            "title": "题解：P3846 【模板】BSGS / [TJOI2007] 可爱的质数",
            "summary": "本文为洛谷 P3846 的题解，用大步小步算法配合哈希表求解离散对数，得到最小的非负整数指数。",
            "date_modified": "2026-06-29T15:20:26.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/math/lattice-operations",
            "content_html": null,
            "url": "https://lailai.one/blog/math/lattice-operations",
            "title": "数学：同构的运算",
            "summary": "本文将介绍 max 与 min、逻辑、集合、命题等运算如何同为格论 join 与 meet 的化身。",
            "date_modified": "2026-06-01T01:33:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "Mathematics"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P6597",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P6597",
            "title": "题解：P6597 烯烃计数",
            "summary": "本文为洛谷 P6597 的题解，牛顿迭代求烷基生成函数，再对双键两端用 Burnside 引理组合。",
            "date_modified": "2026-05-31T15:11:21.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P6598",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P6598",
            "title": "题解：P6598 烷烃计数",
            "summary": "本文为洛谷 P6598 的题解，求烷基生成函数后钦定重心为根容斥，组合点、边、双重心三类生成函数。",
            "date_modified": "2026-05-31T14:30:21.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P3788",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P3788",
            "title": "题解：P3788 幽幽子吃西瓜",
            "summary": "本文为洛谷 P3788 的题解，一道几何题，按两切角关系分类讨论各半圆对红色与可见面积的贡献。",
            "date_modified": "2026-05-12T15:30:24.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/record/ai-multimedia",
            "content_html": null,
            "url": "https://lailai.one/blog/record/ai-multimedia",
            "title": "杂谈：AI 多媒体任务",
            "summary": "本文分享用 AI 完成各类多媒体任务的经验，比较主流模型并按文本、图片、视频等分类总结做法。",
            "date_modified": "2026-05-02T16:00:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "AI",
                "Record"
            ]
        },
        {
            "id": "https://lailai.one/blog/misc/hez-history",
            "content_html": null,
            "url": "https://lailai.one/blog/misc/hez-history",
            "title": "项目：浙江省杭州第二中学校史",
            "summary": "本文整理由 AI 编年汇总的浙江省杭州第二中学大事记，收录 2024 至 2026 年的校园动态。",
            "date_modified": "2026-04-19T16:00:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "Miscellaneous"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P2508",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P2508",
            "title": "题解：P2508 [HAOI2008] 圆上的整点",
            "summary": "本文为洛谷 P2508 的题解，由费马平方和定理分解 r，累乘各 4k+1 型质因子指数求整点个数。",
            "date_modified": "2026-04-14T16:09:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P1999",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P1999",
            "title": "题解：P1999 高维正方体",
            "summary": "本文为洛谷 P1999 的题解，b 维结构等价于选 b 个自由坐标，答案为组合数乘 2 的若干次方。",
            "date_modified": "2026-04-13T14:33:47.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        },
        {
            "id": "https://lailai.one/blog/record/gfssm-2026-qualification",
            "content_html": null,
            "url": "https://lailai.one/blog/record/gfssm-2026-qualification",
            "title": "记录：GFSSM 2026 资格轮",
            "summary": "本文记录参加 GFSSM 2026 空间站设计赛资格轮的全过程，复盘以 AI 为主的工作流与分工。",
            "date_modified": "2026-04-02T14:00:00.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "AI",
                "Record"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/AT_wupc2012_6",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/AT_wupc2012_6",
            "title": "题解：AT_wupc2012_6 最後の問題",
            "summary": "本文为洛谷 AT_wupc2012_6 的题解，枚举对角点定矩形，用二维前缀和判内无点求最大空矩形。",
            "date_modified": "2026-03-21T10:04:22.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "AtCoder"
            ]
        },
        {
            "id": "https://lailai.one/blog/solution/P15649",
            "content_html": null,
            "url": "https://lailai.one/blog/solution/P15649",
            "title": "题解：P15649 [省选联考 2026] 找寻者 / recollector",
            "summary": "本文为洛谷 P15649 的题解，把贡献拆到每条边，用积分恒等式与概率生成函数配合多项式乘除求解。",
            "date_modified": "2026-03-07T05:53:22.000Z",
            "author": {
                "name": "lailai"
            },
            "tags": [
                "OI",
                "Solution",
                "Luogu"
            ]
        }
    ]
}